In right angled triangle ABCIn which angle c=90,if D is the mid point of BC,prove that AB^2=4AD^2-3AC^2
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Answer:
Step-by-step explanation:
GIVEN:
ABC is a right angled at B and D is the midpoint of BC.
In ∆ABD
AD²= AB²+BD²…………(1)
[By Pythagoras theorem]
In ∆ ABC
AC²= AB²+BC²…………(2)
From equation (1)
AD²= AB²+ (BC/2)²
[D is the midpoint of BC]
AD²= AB²+ BC²/4
AD²= AB²/1+ BC²/4
4AD²= 4AB²+ BC²
BC²= 4AD²-4AB²…………….(3)
Using the value of BC² in eq. 2
AC²=AB²+4AD²-4AB²
AC²=AB²-4AB+4AD²
AC²= 4AD²-3AB²
HENCE PROVED….
HOPE THIS WILL HELP YOU…
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