Question

in right angled triangle hypotenuse is 12 and perpendicular is 4 find base​

Answer 1

Step-by-step explanation:

Let us consider a triangle ABC , in which AC is the hypotenuse , AB is the perpendicular side & BC , thd base.

Now,

AC = 12cm

AB = 4cm

By Pythagoras theorem, we know that

AC² = AB² + BC²

$\implies$ 12² = 4² + BC²

$\implies$ 144 = 16 + BC²

$\implies$ 144 - 16 = BC²

$\implies$ 128 = BC²

$\implies$ BC = √128

$\therefore$ BC = 8√2

Hence , the base is 8√2 cm

$\huge\boxed{\fcolorbox{black}{yellow}{HOPE \: IT \: HELPS}}$