Question

in right angled triangle hypotenuse is 17cm and height is 8 cm find the base.. please tell please fast​

Answer 1

Answer:

15cm

Step-by-step explanation:

let the right angle triangle be ABC

in triangle abc, angle abc is 90 degree

now,

by pythagoras theorem,

hypotenuse²=base²+height²

therefore,

AC²=AB²+ BC²

(17) ²=AB²+8²

289=ab²+ 64

ab²=289-64

ab²= 225

ab=15

therefore, base of the triangle is 15cm

Answer 2

Answer:

given -in right angled triangle hypotenuse is 17cm and height is 8 cm find the base.. please tell please fast

Step-by-step explanation:

so friend , see down

let me say ABC is the right angle triangle.

which is right angled at b.

so now according to the given answer, we could say that :

AB is 8 cm( height)

AC is 17 cm (hypotenuse)

andBC is to be find.

by Pythagoras theorem-we have

(hypotenuse)²=(height)² + (base)²

putting values

17²=8²+BC ²

289=64+ BC²(because on evaluating 17 square and 8 square the respective values are 289 and 64)

W

289-64=BC²(because on transposing 64 from left hand side to right hand side it sign changes from + to -)

225=BC²(because on subtracting 64 from 289 we get 225)

OR

BC²=225

(when we remove Square from BC,we transport it towards the left hand side where it becomes under root)

BC=√225(on solving under root 225 we get 15 because 15 × 15 equals to 225,)

BC=√(15×15). {now we will make pair of 15 as there is a pair 15 will come out}

BC=15cm

therefore the value of base is 15 CM

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