Question

in right angled triangle POR, Q=90°,R=0 andif sin0=5/13 then find cos 0 and tan0​

Answer 1

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Answer 2

Answer:

⇒ ∠POR=90

o

[ Given ]

∴ △POR is right-angled triangle.

PO=6cm and OR=8cm [ Given ]

⇒ (PR)

2

=(PO)

2

+(OR)

2

⇒ (PR)

2

=(6)

2

+(8)

2

⇒ (PR)

2

=36+64

⇒ (PR)

2

=100

∴ PR=10cm

Now,

⇒ ∠QPR=90

o

∴ △PQR is right-angled triangle.

⇒ PQ=24cm [ Given ]

⇒ (QR)

2

=(PQ)

2

+(PR)

2

⇒ (QR)

2

=(24)

2

+(10)

2

⇒ (QR)

2

=576+100

⇒ (QR)

2

=676

⇒ QR=26cm