Question

In right-angled triangle PQR, if angle P =60degree, angle R =30degree and PR = 12, then find the values of PQ and QR. ​

Answer 1

Answer:PQ=6

QR= 6root3

Step-by-step explanation:

Answer 2

Answer:

PQ = 6 and QR = 6√3

Step-by-step explanation:

Given:

In Δ PQR, ∠P = 60°, ∠R = 30°

∴∠Q = 180° - (60° + 30°)

∠Q = 90°

PR = 12

To Find:

Values of PQ and QR.

Solution:

In right Δ PQR,

Sin 60° = $\frac{QR}{PR}$       [∵ Sinβ=$\frac{perpendicular}{hypotenuse}$]

⇒$\frac{\sqrt{3} }{2}=\frac{QR}{12}$    [∵ Sin 60° = $\frac{\sqrt{3} }{2}$]

⇒ $\frac{\sqrt{3}*12 }{2}=QR$      

⇒$QR=6\sqrt{3}$

Now,

Sin 30° = $\frac{PQ}{PR}$         [∵ Sinβ=$\frac{perpendicular}{hypotenuse}$]

⇒ $\frac{1}{2}=\frac{PQ}{12}$     [∵ Sin 30° = $\frac{1}{2}$]

⇒ $\frac{12}{2}=PQ$

⇒$PQ=6$

∴ Required Values of PQ = 6 and QR = 6√3

**For more details please see the attachment**

______________________________

              //Hope it will Helped You//

        //Please Mark it as Brainliest//