In right angled triangle PQR, right angle at R, M is the mid-point of hypotenuse PQ. R is joined to M and produced to a pint S such that RM=MS. Point S is joined to point Q so that PQ=2RM.
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Step-by-step explanation:
Answer
C
Solution
RS=12PQ
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Answer:
pt = tq by radius of a circle by using 3 noncollinear points
rt = ts given
angle ptr = angle qts vertically opposite angle
area of ptr = area of it's by congrency of triangles
Step-by-step explanation:
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