Question

in right angled triangled pqr, pq=3√3cm, pr=5√2cm find qr
​

Answer 1

Answer:

In ΔPQR; LQ=90

o

PQ=3cm; PR=6cm

QR=

6

2

−3

2

=3

3

sin(LQPR)=

PR

QR

=

6

3

3

=

2

3

So, LQPR=60

o

⇒ LQRP=30

o

.