Question

In right triangle ABC, ∠A and ∠B are complementary angles and sin A = $\frac{8}{9}$. What is cos B?
choices -
A. $\frac{\sqrt[8]{17}}{17}$
B. $\frac{8}{9}$
C. $\frac{\sqrt[]{17}}{9}$
D. $\frac{\sqrt[]{17}}{8}$

Answer 1

complementary angles means A+B=90

B=90-A

cos B = cos (90-A) = sin A = 8/9

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