Question

in right triangle ABC angle b = 90 degree, AC =17 CM and b'=8 CM determine cosce c , cot a , secA​

Answer 1

Answer:

cosec C=AC/AB=17/15

cotA = AB/BC=15/8

sec A=AC/AB=17/15

Step-by-step explanation:

In the Δ ABC

AB²=AC²-BC²

=289-64=225

AB=15

Now

cosec C=AC/AB=17/15

cotA = AB/BC=15/8

sec A=AC/AB=17/15