in right triangle ABC angle b = 90 degree, AC =17 CM and b'=8 CM determine cosce c , cot a , secA
Answers
Answered by
0
Answer:
cosec C=AC/AB=17/15
cotA = AB/BC=15/8
sec A=AC/AB=17/15
Step-by-step explanation:
In the Δ ABC
AB²=AC²-BC²
=289-64=225
AB=15
Now
cosec C=AC/AB=17/15
cotA = AB/BC=15/8
sec A=AC/AB=17/15
Attachments:
Similar questions