In right triangle ABC, angle b is equal to 90 a circle is drawn with AB as diameter intersecting the hypotenuse AC at P prove that the tangent to a circle at P bisects BC
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actually if you see the whole triangle is made up of the 6 tangent from the circle.
and also tangent meet at the same point outside the circle are equal .
so point p cut the hypotenuse half half.
and if a line is drawn from the hypotenuse half point then it will surely bisect base....
hope it give you a clue
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