in right triangle ABC, angleB =90 degree. find BC, if AC=15m,angle CAB =30 degree
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Cos theta = base/ hypotenuse
cos 30 = base / 15
root 3/ 2×15 = base
BC=12.99 or 13
BRAINLIEST PLEASE
cos 30 = base / 15
root 3/ 2×15 = base
BC=12.99 or 13
BRAINLIEST PLEASE
Answered by
1
the side opposite to 30 degree (CAB ) is halof the hypotenuse(AC)
therefore
,hypotenuse(AC)=15
BC=AC÷1/2
BC=15÷1/2
BC=7.5m
therefore
,hypotenuse(AC)=15
BC=AC÷1/2
BC=15÷1/2
BC=7.5m
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