Question

in right triangle ABC, angleB =90 degree. find BC, if AC=15m,angle CAB =30 degree

Answer 1

Cos theta = base/ hypotenuse
cos 30 = base / 15
root 3/ 2×15 = base
BC=12.99 or 13



BRAINLIEST PLEASE

Answer 2

the side opposite to 30 degree (CAB ) is halof the hypotenuse(AC)
therefore
,hypotenuse(AC)=15
BC=AC÷1/2
BC=15÷1/2
BC=7.5m