Question

in right triangle ABC angleB =90° AB=3cm and AC=6cm find and v and angle a

Answer 1

Using the trignometric principles,

sin (ACB) = AB/AC = 3/6 = 1/2

Thus, angle ACB = 30 degrees

and angle BAC = 90 - angle ACB = 60 degrees

Answer 2

angle a 30 degree..... BC²= AC²-AB²
= 36-9
= 27
BC =
$3 \sqrt{3}$