In right triangle abc right-angled at b if tana=2 then 2sin Acosec c = 4
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tan A = 1 As we know Now construct a right angle triangle right angled at B such that ∠ BAC = θ Hence perpendicular = BC = 1 and base = AB = 1 By Pythagoras theorem, AC2 = AB2 + BC2
⇒ AC2 = (1)2 + (1)2
⇒ AC2 = 2 .
⇒ AC = √2 As,
⇒ 2 sin A cos A=1 = R.H.s
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In right triangle abc right-angled at b if tana=2 then 2sin Acosec c = 4
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