in right triangle ABC right angled at B, sin A =5 ÷13 find tan A
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Sin a=5/13
Sin a=bc/ac
Thus
Bc=5 and ac=13
Using Pythagoras theorem
13^2=5^2+ab^2
169=25+ab^2
ab^2=144
ab=12cm
Now, tan a=bc/ab
Tan a=5/12
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Sin a=bc/ac
Thus
Bc=5 and ac=13
Using Pythagoras theorem
13^2=5^2+ab^2
169=25+ab^2
ab^2=144
ab=12cm
Now, tan a=bc/ab
Tan a=5/12
Pls mark it as brainliest
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