In right triangle ABC right angled at C if CB=AC and angle B=PHI find PHI
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Tantheta=AC/BC ------1
tan phi= AC/DC -------2
:-tan thete/tan phi= DC/BC (divide 1&2)
=DC/(BD+DC)
= DC/2DC (BD=DC)
= 1/2
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Answer:
Tantheta=AC/BC ------1
tan phi= AC/DC -------2
:-tan thete/tan phi= DC/BC (divide 1&2)
=DC/(BD+DC)
= DC/2DC (BD=DC)
= 1/2
Step-by-step explanation:
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