Math, asked by sangeetadas59023, 2 months ago

In right triangle ABC, right angled at C, M is the mid-point of

hypotenuse AB. C is joined to M and produced to a point D

such that DM = CM. Point D is joined to point B (see the given figure).Show that:

(i) 

AMC =BMD

(ii) 

<DBC is a right angle.

(iii) 

DBC =ABC


(iv) CM =1/2 AB

Answers

Answered by SWEETYASH
4

i) △AMC≅△BMD

Proof: As 'M' is the midpoint

BM=AM

And also it is the mid point of DC then 

DM=MC

And AC=DB (same length)

∴Therefore we can say that

∴△AMC≅△BMD

ii) ∠DBC is a right angle

As △DBC is a right angle triangle and

DC2=DB2+BC2 (Pythagoras)

So, ∠B=90°

∴∠DBC is 90°

iii) △DBC≅△ACB

As M is the midpoint of AB and DC. So, DM=MC and AB=BM

∴DC=AB (As they are in same length)

And also, AC=DB

and ∠B=∠C=90°

By SAS Axiom

∴△DBC≅△ACB

iv) CM=21AB

As △DBC≅△ACB

CM=2DC

∴DC=AB(△DBC≅△ACB)

So, CM=2AB

∴CM=21AB

Answered by Anonymous
8

Answer:

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