Question

In right triangle $PQR$, we have $\angle Q = \angle R$ and $PR = 6\sqrt{2}$. What is the area of $\triangle PQR$?

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:36

A triangle can't have two right angles, so a right triangle with two congruent angles must have congruent acute angles. That is, triangle PQR must be an isosceles right triangle with acute angles at Q and R. Therefore, PQ=PR=6sqrt2, and QRP=(QP) (RP)/2 = (6sqrt2)(6sqrt2)/2 = (6*6*sqrt2*sqrt2)/2 =36.