Question

in rightangled trianglePSR,seg ps is perpendicular to seg RQ,seg QT perpendicular to seg PR,point Q lies on segRS,segPQ is hypotenus of rightangled trianglePSQ if RQ=6,PS=6,PR=12,then find QT

Answer 1

this will help you.
so try to understand this .

Answer 2

Answer:

Given:

PS ⊥ RQ

QT ⊥ PR

RQ = 6, PS = 6 and PR = 12

With base PR and height QT,

A(△PQR)=½×PR×QT

With base QR and height PS,

A(△PQR)=½×QR×PS

∴A(△PQR)/A(△PQR)=½×PR×QT/½×QR×PS

⇒1=PR×QT/QR×PS

⇒PR×QT=QR×PS

⇒QT=QR×PS/PR

=6×6/12

=3

Hence, the measure of side QT is 3 units.