in ripple tank 40 waves pass through a certain point in 1 second. If wavelength of wave is 5cm then find the speed of wave
Answers
The speed of the wave is equal to 2 ms⁻¹.
Given:
Number of waves passing through a certain point in 1 second = 40 waves
The wavelength of the wave (λ)= 5 cm
To Find:
The speed of the wave.
Solution:
Let the speed of the wave be 'v'.
→ The frequency of a wave is equal to the number of waves passing through a given point per unit of time. It is denoted by 'f'.
→ The wavelength of a wave is equal to the distance between two consecutive crests or two consecutive troughs. It is denoted by 'λ'.
→ The speed of a wave is equal to the product of its frequency (f) and wavelength (λ).
→ In the given question:
→ The wavelength of the wave (λ) = 5 cm = 0.05 metre
→ As 40 waves are passing through a certain point in 1 second, therefore the frequency of the wave would be equal to 40 Hz.
∴ Speed of the wave (v) = Frequency (f) × Wavelength (λ)
∴ v = f × (λ)
∴ v = 40 × (0.05) = 2 ms⁻¹
Therefore the speed of the wave is equal to 2 ms⁻¹.
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The wave speed is equal to ms⁻¹.
Answer:
Number of waves passing through a certain point in second = waves
The wavelength of the wave (λ)= cm
Find:
Wave speed.
Solution:
Let the speed of the wave be 'v'.
The frequency of a wave is equal to the number of waves passing through a given point per unit of time.
The wavelength of a wave is equal to the distance between two consecutive peaks or two consecutive troughs. It is denoted by 'λ'.
The speed of a wave is equal to the product of its frequency (f) and its wavelength (λ)
In the given question:
the wavelength of the wave (λ) = cm = meter
Since waves pass through a certain point in 1 second, the frequency of the wave would be Hz.
Wave speed(v)=frequency(f)*wavelength(λ)
Hence λ
Hence
Therefore, v=
Therefore, the speed of the wave is equal to 2.
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