Question

In RLC series circuit R = 1.5 ohm, L = 0.2 H, C = 100 microF . Find Q factor

Answer 1

Answer:

Explanation:In RLC series circuit R = 1.5 ohm, L = 0.2 H, C = 100 microF . Find Q factor

Answer 2

Answer:

The Q factor is 29.81.

Explanation:

The Q-factor is given as,

$Q=\frac{2\pi f L}{R}$      (1)

Where,

Q=qlaity factor or q factor

f=resonant frequency

L=inducatnce

R=resistance of the resistor

From the question we have,

R=1.5Ω

L=0.2H

C=100μF=100×10⁻⁶F

The resonant frequency is calculated as,

$f=\frac{1}{2\pi\sqrt{LC} }$    (2)

By substituting the value in equation (2) we get;

$f=\frac{1}{2\pi\sqrt{0.2\times 10^-^4} }$  

$f=\frac{223.6}{2\pi}$    (3)

By substituting all the required values in equation (1) we get;

$Q=\frac{2\pi\times \frac{223.6}{2\pi} \times 0.2}{1.5}$

$Q=\frac{44.72}{1.5}$

$Q=29.81$

Hence, the Q factor is 29.81.