in running from a station A to a station B,a train travels at 7/9th of its usual speed.if it takes n times the usual time,then the value of n is options are 7/9,7,9/7 and 9
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Answer:9/7
Step-by-step explanation:
as let's try to simplify it . Assume train has Sep of 1km/hr. So it will run at 7/9 km/hr. So if it has to travel one unit suppose so it will be: distance to travel/speed
=1÷7/9=9/7
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