in S₂O₈²− calculate the oxidation no.of sulphur
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Answer: The chemical formula of the given ion is S2O82-.
Let us assume the oxidation state of the sulphur (S) is X.
There are total eight oxygen(O) atoms, out of which two involve in peroxide linkage with oxygen state (-1) and remaining six oxygen(O) atoms, having oxygen state (-2).
Total charge on compound is
2 × X + 2× (-1) + 6× (-2) = -2
2X – 2 – 12 = -2
2X – 14 = -2
2X = 12
X = +6
∴ The oxygen state of the sulphur in the given ion is +6.
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