Question

In S4O6 2- ion, oxidation numbers of sulphur atoms
are
(1) 5, 0, 0,5
(2) 2, 2, 2, 2
(3) -2, 0, 0, +2 (4) 4, 0, 0, 6​

Answer 1

+6

The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The oxidation number of the sulfur atom in the SO42- ion must be +6, for example, because the sum of the oxidation numbers of the atoms in this ion must equal -2.

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