Question

In scattering experiment find the distance of closest approach if a 6Mev alpha particle is used

Answer 1

Answer:

Distance of closet approach of an α-particle is given by,

r=Kα2kZe2

ATQ, Z=79

Kα=6MeV=6×1.6×10−13J

Substituting these values we get,

r=6×1.6×10−132×9×109×79×(1.6×10−19)2=3.792×10−16m