Math, asked by aveshp648, 3 months ago

) In Section A, 45 students out of 50
passed. In Secion B, 5 out of 60 failed.
Which section had better results?​

Answers

Answered by ᏟrєєpyᎷєss
38

Section A

Total student = 50

students passed = 45

.°. passing % = \sf{\dfrac{45}{50}×100=90}

Section B

Total students = 60

Students passed = 60 - 5 = 55

.°. passing % = \sf{\dfrac{55}{300}×100=91.44}

Passing % of section B is greater than A section by 44 %

Section B had Better Rresults

Answered by Kashmita333
2

Answer:

In Section A

 \frac{45}{50}

are passed.

In Section B

 \frac{05}{60}

are failed.

Therefore, The Section had better results

In A Section

Total Students is 50.

45 Students passed.

( 50-45) = 5 Students is failed.

In B Section

Total students is 60.

(60-5) = 55 students are passed.

5 students is failed.

But

In section A is 50 and B is 60

And 10 students extra in B

So the Answer is equall.

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