In section a there are 20 boys and 20 girls while in section b there are 15 boys and 25 girls.one student is chosen from both sections. What is the probability of both being girls.
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Answer:
Step-by-step explanation:
In section A
Number of Boys=20
Number of Girls=20
Total number of students in section A= 20+20
=40
In section B
Number of Boys=15
Number of Girls=25
Number of students in section B=15+25
=40
Total number of students in both sections= section A + section B
=20+40
=60
P(E) =p(both be girls)
= 20+25/60
=45/60
=9/12
=3/4
Hope you understand......
I tried my best to execute my knowledge........
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