In , seg AB ≅ seg AD , seg BC ≅ seg CD. Prove that seg AC bisects m∠A
and m∠C
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Step-by-step explanation:
In ΔABD and ΔCBD
AB=CB (Given)
AD=CD (Given)
BD=BD (Common)
By SSS test of congruency
ΔABD≅ΔCBD
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