Question

In series LCR circuit L=1H, C=1micto farad and R=20 ohm is connected across a supply voltage of 10 volt. At resonance voltage across L is

Answer 1

We know that condition of resonance is ${w}^{2} = \frac{1}{LC}$

Now, given L = 1 H , C = 1 mF = 1 × 10^-6 F.

Thus, we get w =

$\frac{ 1}{ \sqrt{LC} } \\ = \frac{1}{ \sqrt{ {10}^{ - 6} } } \\ = \frac{1}{ {10}^{ - 3} } \\ = {10}^{3}$

Now, at resonace , Impedance of the circuit(Z) = R.

Hence, Current through the circuit = $\frac{v}{z} \\ = \frac{V}{R} \\ = \frac{10}{20} \\ = 0.5$

Hence, I = 0.5

Now, inductive reactance ( Resistance of Inductor) = w L

= 1000 × 1 = 1000.

Hence, voltage across inductor = I × wL = 0.5 × 1000 = 500 Ans.

Answer 2

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