Question

In shop cost price of product A & product B is in ratio of 21:31, total cost of product A & product B is 520 rupes. what is cost price for individual products.​

Answer 1

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➠ In shop cost price of product A & product B is in ratio of 21:31, total cost of product A & product B is 520 rupees. What is cost price for individual products.​

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❏ In this type of problem we have to assume a variable to solve the question.

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❏ Then we have 2 variable and 2 equations, so using using substitution method we can get our answer easily.

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➠ Ratio = 21 : 31

➠ Sum of amount = 520

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$\underline{\boxed{\bold{\bigstar \; Answer \; \bigstar}} }$

Let's Start !

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Let's assume following things !

• Cost of Product A = x

• Cost of Product B = y

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Now let's write given condition .-.

As ratio of price of both product is 21 : 31

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$\bold { :\implies \dfrac{x}{y} = \dfrac{21}{31} }$

$\bold { :\implies x = \dfrac{21\times y}{31} }$

$\boxed { \bold { \orange { :\leadsto x = \dfrac{21y}{31} } } }$

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Now let's have a look on second condition !

Sum of price of both products is 520.

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$\bold { :\implies x + y = 520 }$

$\bold { :\implies \dfrac{21y}{31} + y = 520 }$

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$\bold { :\implies 21y+ 31y = 520 \times 31 }$

$\bold { :\implies 52y = 520 \times 31 }$

$\bold { :\implies y = `10 \times 31 }$

$\boxed { \bold { \red { :\longmapsto \; y = `310 } } }$

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Now let's find value of "x"

$\bold { :\implies x = \dfrac{21\times y}{31} }$

$\bold { :\implies x = \dfrac{21\times 310}{31} }$

$\bold { :\implies x = 21 \times 10 }$

$\boxed { \bold { \red { :\longmapsto \; x = 210} } }$

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$\boxed { \boxed { \bold { \therefore Cost \; Price \; of \; Product \; A = Rs.210} } }$

$\boxed { \boxed { \bold { \therefore Cost \; Price \; of \; Product \; B = Rs.310} } }$

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