Question

In shuffling a pack of cards 3 are
accidently dropped, then the
chance that missing card should be
of different suits is?​

Answer 1

Answer:

6561 / 62475

Step-by-step explanation:

Probability of the first card to be from any suit = 1 (can be any card)

Probability of the second card to be from any other suit =

Favorable cards = 52 (Total no. of cards) - 13 (cards from the first suit) = 39

Total remaining cards to choose from = 52 - 1 (one card is already removed)

P(E) = 39 / 51

Similarly., P(E) of the other 2 cards will be 26 / 50 = 13 / 25 , and 13 / 49.

Total probability = 1*39*13*13 / 51*25*49

                            = 6561 / 62475

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