In shuffling a pack of cards, four are accidently dropped, find the chance that the dropped cards should be one from each suit.
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Answer:
6561 / 62475
Step-by-step explanation:
Probability of the first card to be from any suit = 1 (can be any card)
Probability of the second card to be from any other suit =
Favorable cards = 52 (Total no. of cards) - 13 (cards from the first suit) = 39
Total remaining cards to choose from = 52 - 1 (one card is already removed)
P(E) = 39 / 51
Similarly., P(E) of the other 2 cards will be 26 / 50 = 13 / 25 , and 13 / 49.
Total probability = 1*39*13*13 / 51*25*49
= 6561 / 62475
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