Question

in side of triangle and a b c respectively if s-a =10 s-b=15 and s-c =12​

Answer 1

Answer:

Step-by-step explanation:

(s-a) + ( s-b) + ( s-c) =10+15+12=37

3s-(a+b+c)=37

3s=37+(a+b+c)

3\2(a+b+c) =37+(a+b+c)

3(a+b+c)=74 + 2 (a+b+c)

(a+b+c) = 74

3s = 37+74

3s =  111

s= 111\3

s= 37

=>s-a=10

37-a=10

a=27

=> s-b = 15

37-b=15

b=22

=>s-c=12

37-c=12

c=25

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