Question

in side QR of triangle PQR is produced to s.If angle PRS=132 and angle RQP=37 find angle QPR and angle PRQ​

Answer 1

Answer:

the answer is in the pic

Answer 2

$\large{\underline{\bf{\purple{Given:-}}}}$

• ✦∠PRS = 132°
• ✦ ∠RQP = 37

$\large{\underline{\bf{\purple{To\:Find:-}}}}$

• ✦ ∠PRQ
• ✦ ∠QPR

$\huge{\underline{\bf{\red{Solution:-}}}}$

QR of triangle ∆ PQR produces to s

Then,

∠132 + ∠PRQ = 180° [Linear pair]

∠PRQ = 180 - 132

∠PRQ = 48

So,

∠PRQ = 48°

Now,

∠PRQ + ∠QPR + ∠RQP = 180°

[ sum of all angles of ∆ is 180°]

48 + ∠QPR + 37 = 180

∠QPR + 85 = 180

∠QPR = 180 - 85

∠QPR = 95

SO,

∠QPR = 95°

hence ,

• ∠QPR = 95°
• ∠PRQ = 48°

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