Question

In simple interest, a sum of money amounts to ₹ 6,200 in 2 years and ₹ 6,800 in 3 years. Find

the principal and rate of interest.​

Answer 1

Answer:

si for 1 yr= 6800-6200 = 600

so si for 2 yr = 1200

so p = 6200 - 1200 = 5000

and r = (600/5000)*100 = 12%

Answer 2

Answer:

Principal amount = 5000₹, Rate of interest = 12%

Step-by-step explanation:

If A = 6200₹

⇒ Principal + interest for 2 years = 6200₹

A = 6800₹

⇒ Pricipal + interest for 3 years = 6800₹

Difference gives the interest for 1 year

∴ Interest for 1 year = 6800 - 6200 = 600₹

Interest for 2 years = 2 ×600 = 1200₹

Principal = Amount - S.I

Principal = (A) - (S.I) = 6200 - 1200 = 5000₹

Let R% p.a be rate of interest

R = $\frac{(S.I)(100)}{(P)(T)}$%

    = $\frac{(1200)(100)}{(5000)(2)} %$%

     = 12%

Rate of interest  = 12%

Therefore, Principal amount = 5000₹, Rate of interest = 12%