Question

In Sin A=3/5 than find tanA and secA? ​

Answer 1

Answer:

if sinA = 3/5 than, p = 3 & h = 5 so , b^2 = (h)^2-(p)^2 b^2 = (5)^2 -(3)^2 b^2 = 25-9 b = 4 tanA = p/b = 3/4