In sinA=3/4,calculate cosA and tan A .
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cosA=4/5 and tanA=3/4
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sinA=p/h=3/4
p=3, h=4
b=√4sq-3sq
b=√16-9
b=√7
so cosA= b/h=√7/4
tanA=p/b= 3/√7
p=3, h=4
b=√4sq-3sq
b=√16-9
b=√7
so cosA= b/h=√7/4
tanA=p/b= 3/√7
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