Chemistry, asked by yaaronkiyaari23, 1 month ago

In SN² reactions , the sequence of bond breaking and bond formation is as follows _________________. *
bond breaking is followed by formation
bond formation is followed by breaking
bond breaking and formation take place simultaneously
bond breaking and formation take place randomly

Answers

Answered by vpaul4185
0

Answer:

Bond breaking and formation take place simultaneously.

Some more points about SN² rxn:

Order of SN² rxn is 2.

Stereochemistry of the molecule changes.

Reactivity order towards SN² is 1°>2°>3°.

Answered by qwcasillas
0

Bond breaking and a new bond formation occur simultaneously in a S_{N} 2 reaction.

  • S_{N} 2 reaction is a nucleophilic substitution reaction that follows second-order kinetics.
  • The rate-determining step in the reaction is the formation of the transition state, where two reactants are involved. So it is a second-order reaction.
  • A leaving group is replaced by a nucleophile, forming the desired product. The attack of nucleophiles occurs from the backside of the carbon with leaving group, forming a transition state.
  • So less crowded carbons favor S_{N} 2 reactions. the order of reactivity towards the S_{N} 2 mechanism is 3°<2°<1°<methyl carbon.
  • Examples of a reaction involving S_{N} 2 mechanism include the formation of alcohols from alkyl halides.
  • The general reaction mechanism is shown in the given attachment.

                                 

Attachments:
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