Chemistry, asked by shweta8cdavrtk, 8 months ago

In sodium oxide, having the antifluorite structure, the co-
ordination number of sodium ion (Na+) and oxide ion
(02-) respectively are
8 and 4
4 and 8
4 and 4
8 and 8​

Answers

Answered by Ronney321
9

Answer:

ion is surrounded by four oxide ions and ion is surrounded by eight ions. Hence the "coordination number" of Na in is 4. So the coordination number of oxide ion in sodium oxide is eight and the coordination number of sodium ion in sodium oxide is 4.

Answered by Anonymous
4

In sodium oxide, having the antifluorite structure, the co ordination number of sodium ion (Na+) and oxide ion  (02-) is 4 and 8

  • Na+ ( Sodium) is in a tetrahedral void and represents four specific ions in the oxide Na2O.
  • The Na+ ions are typically surrounded by four oxide ions, whereas specific O2 ions are surrounded by eight ions.
  • So, in the sodium oxide ( Na2o) the Na (Sodium) ions coordination number is 4 and that of oxide ion is 8.
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