Question

In solanum flower each locule at maturity has 40 ovules out of which 20 percent become abortive. how many number of meiotic divisions are needed for development of remaining fertile ovules into seeds​

Answer 1

Answer:

Number of ovules in a locule = 10

Number of reduced ovules = 10%

10% of 10 = 10100× 10 = 1

Thus, the remaining functional ovules = 9.

An ovule generally has single embryo sac formed from megaspore though single meiotic division. Thus, each ovule is changed into single seed after fertilisation.

Thus, 9 meiotic divisions one in each ovule are required for the development of remaining fertile ovules into seeds.

Answer 2

Answer:

16

Explanation:

solanum flowers are bilocular,

since each locule contain 40 ovules, total number of ovules is 80 in which 20% is abortive which implies , only 64 ovules develop into seeds.

64 ovules develop from 16 pollen grains.

so 16 pollen grains undergo 16 meiotic divisions.

ans=16

hope this answer may help you......