Question

in) solve : 14=3y+x;20=2y-3x​

Answer 1

Answer:

y=4,

Explanation:

14=3y+x

put x =2

14=3y+2

14-2=3y

12=3y

12/3=y

4=y

y=4

Answer 2

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To solve :-

$14 = 3y + x ->eqn(i) \\ 20 = 2y - 3x ->eqn(ii)$

Solution :-

$(3y + x = 14) \times 2 \\ (2y - 3x = 20) \times 3$

Multiplying eqn(i) with 2 and eqn(ii) with 3

$6y + 2x = 28 \\ 6y - 9x = 60$

$⇒ \: 6y + 2x = 28 \\ \: \: \: \: \: \: \: 6y - 9x = 60 \\ \: \: \: \: ( - ) \: \: \: \: ( + ) \: \: \: \: ( - ) \\ ⇒ \: \: \: \: \: \: \: \: \: \: 11x = - 32$

$x = \frac{ - 32}{11}$

Putting the value of x in eqn(i)

$⇒3y + x = 14 \\ ⇒3y + \frac{( - 32)}{11} = 14 \\ ⇒3y = 14 + \frac{32}{11} \\ ⇒3y = \frac{14 + 32}{11} \\ ⇒3y = \frac{154 + 32}{11} \\ ⇒3y = \frac{186}{11} \\ \\⇒ y = \frac{186}{11 \times 3} \\ y = \frac{62}{11}$