Math, asked by kneetu1175, 9 months ago

In solving a quadratic equation, Mahendar made a mistake in taking the product of the roots and got roots of equation as 5 and 1. Niranjan made a mistake in taking the sum of roots and got roots of equation as 8 and 1. What are the actual roots of the equation?

Answers

Answered by shibanshu6629
0

Answer:

5,4

online test 2023 MOT ,Q.75

Step-by-step explanation:

Answered by sonuvuce
0

The actual roots of the equation are 2 and 4

Step-by-step explanation:

Let the actual roots of the equation are \alpha and \beta

Quadratic equation whose roots are 5 and 1 has correct sum of roots

Thus,

\alpha+\beta=5+1=6

Quadratic equation whose roots are 8 and 1 has correct product of roots

Thus,

\alpha\beta=8\times 1

\implies \beta=\frac{8}{\alpha}

Therefore,

\alpha+\frac{8}{\alpha}=6

\implies \alpha^2-6\alpha+8=0

\implies \alpha^2-4\alpha-2\alpha+8=0

\implies \alpha(\alpha-4)-2(\alpha-4)=0

\implies (\alpha-4)(\alpha-2)=0

\implies \alpha=4,2

If we take \alpha=4

Then \beta=2

If we take \alpha=2

Then \beta=4

Therefore, the actual roots of the equation are 2 and 4

Hope this answer is helpful.

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