Question

In some harbours, the rise and fall of the water level is simple harmonic. In one such harbour, the

equation for the depth h of the water is
h=5.0+3.0sin(2×3.14×t/45600)



where h is given in metres and t is the time in seconds. (The angle 2πt/45600 is in radians.)

For this harbour, calculate

(1) the maximum depth of water,

(2) the minimum depth of water,

(3) the time interval between high- and low-water,

(4) two values of t at which the water is 5.0 m deep,

(5) the length of time for each tide during which the depth of water is

more than 7.0 m.

Answers
(1)8 m
(2)2 m
(3)22800 sec
(4) 22800, 45600 sec
(5) 12200 sec
•need solution ​

Answer 1

Answer:

it's calculation will be lengthy.

I am too lazy. sorry bro