Chemistry, asked by hemak7469gmailcom, 5 months ago

In specific condition of N/50 KCL of solution is .002765mho cm calculaye the equivalent conductance​

Answers

Answered by kundanconcepts800
0

Answer:

equivalent conductance = k(kappa)×1000/N

= 0.002765×1000/(1/50)

= 2.765×50 mho cm^2 /gequivalent

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