Social Sciences, asked by aryavirbhasin, 6 months ago

"In spite of an overall unity in climate pattern, variations exist in temperature and
precipitation. Explain the given statement in context of India with the help of suitable examples.



pls tell I'll mark brainliest too​

Answers

Answered by rajguttedar3
0

Explanation:

"In spite of an overall unity in climate pattern, variations exist in temperature and

precipitation. Explain the given statement in context of India with the help of suitable examples.

pls tell I'll mark brainliest too

Answered by MrVampire01
1

Explanation:

We Should Know Some Trignometric Identities For Solving This Question.

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\begin{gathered}1. \: \: \sin(2 \alpha ) = 2 \sin( \alpha ) \cos( \alpha ) \\\end{gathered} </p><p>1.sin(2α)=2sin(α)cos(α)

2. \: \: \sin(180 - \alpha ) = \sin( \alpha )2.sin(180−α)=sin(α)

3. \: \: \sin(90 - \alpha ) = \cos( \alpha )3.sin(90−α)=cos(α)

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L.H.S :- Sin10. Sin30. Sin50. Sin70

\begin{gathered}= \cos(90 - 10) \sin(30) \cos(90 - 40) \cos(90 - 70) \\ = \cos(80) \: \frac{1}{2} \: \cos(40) \: \cos(20) \\ = \frac{1}{4 \sin(20) } \cos(8 0 ) \cos(40) . \: 2 \sin(20) \cos(20) \\ = \frac{1}{8 \sin(20) } \cos(80) 2. \cos(40) \sin(40) \\ = \frac{1}{16 \sin(20) } 2 \cos(80) \sin(80 ) \\ = \frac{1}{16 \sin(20) } \sin(160) \\ = \frac{1}{16 \sin(20) } \sin(180 - 20) \\ = \frac{1}{16 \sin(20) } \sin(20) \\ = \frac{1}{16} \: \: \: \: \: \: \: \: .........R.H.S\end{gathered}

=cos(90−10)sin(30)cos(90−40)cos(90−70)

=cos(80) 2/1

cos(40)cos(20)= 4sin(20)1

cos(80)cos(40).2sin(20)cos(20)= 8sin(20)1

cos(80)2.cos(40)sin(40)= 16sin(20)1

2cos(80)sin(80)= 16sin(20)1

sin(160)= 16sin(20)1

sin(180−20)= 16sin(20)1

sin(20)= 16/1

.........R.H.S,

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