Question

In sport day activities of Delhi public school the lines were drawn with chalk powder in rectangular shape OBCD.Each lines in 1/2meter distance from each other.60 flower post have been placed at a distance of 1/2 meter from each other along OD.yamini runs 1/4th and make a red flower.kamala runs 1/5th of the distance OD on the 7th line and makes a yellow flower.find the position of a red and yellow flower and also find the distance between them​

Answer 1

•60 flower post have been placed at a distance of 1/2 meter from each other along OD

• length of OD =60*1/2= 30m

• Position of red flower = 1/4th of OD =1/4×30 = 7.5m

•7th line is at 3.5m

• 1/5th of OD from 3.5m is 3.5 + 6= 9.5 m

• position of yellow flower is at 9.5m

• distance b/w red and yellow flower is 2m

Answer 2

The position of a red and yellow flower is A(1.5 , 7.5) & H (3.5 , 6)

The distance between them is 2.5 m

Step-by-step explanation:

[FIGURE OF THIS QUESTION IS IN THE ATTACHMENT]

SOLUTION IS IN THE ATTACHMENT

Given distance between two flower pots is ½ m and there are 60 flower pots along OD. Also Distance between these two lines is ½ m.

Let us consider x axis along OB and y axis along OD.

Then the X coordinate of position of any student in the field will be obtained by multiplying the distance between two lines by number of line and Y coordinates will obtained by multiplying the given fraction with the Distance OD= 30 cm.

HOPE THIS WILL HELP YOU....

Similar questions :

If the points (2,1)and (1.-2)are equidistant from the points (x,y) show that x+3y=0

https://brainly.in/question/3062701

Find the values of (x,y) if the distance to the point X, Y from (-3, 0) as well as from (3,0) are 4

https://brainly.in/question/7043507