Question

In square ABCD,AD=

A.√2AC B.AC/√2
C.√2/AC D.2AC

(This question is asked in board exam)

Answer 1

We know that all sides of square are equal, all sides are perpendicular to each other.


Here, 

AC = Diagonal
AD = side

Now,
By Pythagoras Theorem,

AD² + AD² = AC²

2AD² = AC²

AD² = AC²/2

AD = $\sqrt{ \frac{AC^2}{2} }$

AD = $\frac{AC}{ \sqrt{2} }$






option C is correct



i hope this will help you


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