in square ABCD, if AB =(5x+4)cm, BC=(7x-10)cm. find the value of x and length of AD??
Answers
Answered by
0
Answer:
7, 39√2
Step-by-step explanation:
in a square all sides are equal. so,
AB= BC
5x+4=7x-10
x= 7
AB = 39
length of AD is the length of diagonal
diagonal of square = side*√2
AD =39√2
Answered by
2
Answer:
x=7
AD=39
Step-by-step explanation:
All the sides are equal so:
5x + 4 = 7x - 10
on transposing we get
10 + 4 = 7x - 5x
14 = 2x
14/2 = x
x = 7
AD = 5x + 4
AD = 5 x 7 + 4
AD = 35 + 4
AD = 39
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