Math, asked by summu53, 8 months ago

in square ABCD, if AB =(5x+4)cm, BC=(7x-10)cm. find the value of x and length of AD??​

Answers

Answered by lakkamakhila
0

Answer:

7, 39√2

Step-by-step explanation:

in a square all sides are equal. so,

AB= BC

5x+4=7x-10

x= 7

AB = 39

length of AD is the length of diagonal

diagonal of square = side*√2

AD =39√2

Answered by prakrutibhaskar
2

Answer:

x=7

AD=39

Step-by-step explanation:

All the sides are equal so:

5x + 4 = 7x - 10

on transposing we get

10 + 4 = 7x - 5x

14 = 2x

14/2 = x

x = 7

AD = 5x + 4

AD = 5 x 7 + 4

AD = 35 + 4

AD = 39

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