In square ABCD, IF AB = (5x + 4) cm, BC = (7x - 10)cm. Find the value of x and length of AD. Jjj
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Reffer to the above attachment.
X=7
AD=39
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Answer:
AB = BC = CD = AD.....( ALL sides of square are equal)
5x + 4 = 7x - 10.
On transposing we get,
10 + 4 = 7x - 5x
14 = 2x
14/2 = x
x = 7
AD = 5x + 4
AD = 5( 7 ) + 4
AD = 35 + 4
AD = 39
Therefore, the value of x is 7 and the length of AD is 39 cm.
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