in square ABCD SEG AD parallel SEG B.C. diagonal BD intersect each other in point p. then show that ap apoun pd is equal to pc apoun BP
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In the attachment I have answered this problem.
To prove this result I have drawn XY such that XY Parallel to BC and passing through P.
Equations 1 and 2 is obtained by applying Thale's theorem in triangles ABC and BCD .
Required is derived from equations 1 and 2.
I hope this answer help you
To prove this result I have drawn XY such that XY Parallel to BC and passing through P.
Equations 1 and 2 is obtained by applying Thale's theorem in triangles ABC and BCD .
Required is derived from equations 1 and 2.
I hope this answer help you
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