Question

in square ABCD SEG AD parallel SEG B.C. diagonal BD intersect each other in point p. then show that ap apoun pd is equal to pc apoun BP

Answer 1

In the attachment I have answered this problem.

To prove this result I have drawn XY such that XY Parallel to BC and passing through P.

Equations 1 and 2 is obtained by applying Thale's theorem in triangles ABC and BCD .

Required is derived from equations 1 and 2.

I hope this answer help you