Question

In square ABCD(side) 10 and diagonal AC,DE is drawn to the side BC with BE=3cm The intersection point of AC and DE is O.Find ratio of area of DOC,BEOA

Answer 1

Answer:

Step-by-step explanation:  Let the angles of the quadrilateral be 3x, 5x, 9x and 13x.           ∵ Sum of all the angles of quadrilateral = 360°           ∴ 3x + 5x + 9x + 13x = 360°           ⇒ 30x = 360°                      ∴ 3x = 3 × 12° = 36°                5x = 5 × 12°= 60°                9x = 9 × 12° = 108°                13x = 13 × 12° = 156°           ⇒ The required angles of the quadrilateral are 36°, 60°, 108° and 156°